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A rectangular garden of length l metres and width w metres has to be fenced and decorated. A wire fence is to be laid along the length costing rupees 100 per metre and a wooden fence is to be built along the width costing rupees 80 per metre. Special seeds have to be sown throughout the garden which will cost rupees 50 per square metre.

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The total cost of decorating the garden is found by adding fencing and seed costs. Wire fencing costs 200l rupees, wooden fencing costs 160w rupees and seeds cost 50lw rupees. Therefore, total cost equals 200l + 160w + 50lw.

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  1. For the rectangular garden, wire fencing is needed along the length and wooden fencing along the width. Since the garden has two lengths and two widths, the wire fencing cost becomes 200l rupees and the wooden fencing cost becomes 160w rupees. The area of the garden is lw square metres, so the seed cost becomes 50lw rupees. By adding all these costs together, we get the algebraic expression for the total cost as 200l + 160w + 50lw.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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