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The current sensitivity of a moving coil galvanometer increases by 35%, when its resistance is increased by a factor 3. The voltage sensitivity of galvanometer changes by a factor

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Poll Results

0%(A) 35%
0%(B) 45%
75%(C) 55% ( 3 voters )
25%(D) None of the above ( 1 voter )
Based On 4 Votes

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The voltage sensitivity of a galvanometer is given by:
Voltage Sensitivity = Current Sensitivity/R
If current sensitivity increases by 35% and resistance increases by a factor of 3,
voltage sensitivity changes by:
Change = 1.35/3 = 0.45 or 45%
Answer: (B) 45%

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1 Answer

  1. The current sensitivity of a moving coil galvanometer is given by:
    Si = N AB/K
    Where:
    N = Number of turns
    A = Area of coil
    B = Magnetic field
    K= Torsional constant
    When the resistance (R) of the galvanometer increases by a factor of 3, the voltage sensitivity (Sv) is given by:
    Sv = Si/R
    Since current sensitivity increases by 35%, we have:

    Sv′ = 1.35 × Si/3R = 1.35/3 × Sv = 0.45 ​× Sv
    Hence, the voltage sensitivity decreases by 55% (100%−45%
    Answer: (C) 55%

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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