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Two batteries with emf 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between
Using the formula for parallel battery circuits:
V = 12/1 + 13/2 /1/1 + 1/2 = 12 + 6.5/1.5 = 11.67V
Thus, the answer is (a) 11.6 V to 11.7 V.
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