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In a wheatston’ bridge, P = 2 Ω, Q = 2 Ω, R = 2 Ω and S = 3 Ω. The resistance with which 5 is to be shunted in order that the bridge may be balanced is
For balance in a Wheatstone bridge:
P/Q = Rshunted/Seffective
Solving for R_shunted, we get 2Ω.
Correct answer: (b) 2Ω.
Class 12th Science Physics NCERT MCQ Questions
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