The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm³ of wood has a mass of 0.6 g.

Inner radius of cylindrical pipe r = 24/2 = 12 cm, outer radius R = 28/2 = 14 cm and lenght h = 35 m
Volume of cylindrical wooden pipe = π(R² – r²)h
= 22/7 × (14² – 12²) × 35 = 22 × (196 – 144 ) × 5 = 22 × 52 × 5 = 5720 cm³
Mass of cylindrical wooden pipe = 5720 × 0.6 g = 3432 g = 3.432 kg [∵ 1 cm³ of wood has a mass of 0.6 g]
Hence, the volume of cylindrical wooden pipe is 3.432 kg.