Rajiv Tyagi
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Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.

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NCERT Solutions for Class 9 Maths Chapter 11
Important NCERT Questions
Constructions
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 11.2
Page No:195
Questions No: 5

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-11/

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  2. Steps of construction
    (i) Draw a line segment AB = 12 cm.
    (ii) At point A, Using ruler and compass, draw an angle ∠BAX = 90°.
    (iii) Taking A as centre and 18 cm as radius, draw an arc which intersect AX at D.
    (iv) Join B to D. Draw a perpendicular bisector (MN) of BD which intersects AD at C.
    (v) join B to C. Triangle ABC is the required triangle.
    Justification
    Point C lies on the perpendicular bisector of BD.
    So, BC = CD
    Here, AD = AC + CD
    ⇒ AD = AC + BC [∵ BC = CD]

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