Nidhi Baghel
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Evaluate the following trigonometry questions?

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(i) (sin 18°)/(cos 72°)
(ii) (tan 26°)/(cot 64°)
(iii) cot 48° – sin 42°
(iv) cosec 31° – sec 59°
NCERT Class 10 Chapter 8 Introduction to trigonometry
Page No. 189
Exercise 8.3
Question No. 1

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1 Answer

  1. (i) (sin 18°)/(cos 72°)
    = (sin 18°)/(cos 72°) = cos (90° – 18°))/(cos 72°) [∵ cos (90° – θ) = sin θ]
    = (cos 72°)/(cos 72°) = 1

    (ii) (tan 26°)/(cot 64°)
    = (tan 26°)/(cot 64°) = (cot (90° – 26°))/(cot 64°) [∵ cot (90° – θ) = tan θ]
    = (cot 64°)/(cot 64°) = 1

    (iii) cot 48° – sin 42°
    = cot 48° – sin 42° = cos 48° – cos (90° – 42°) [∵ cos (90° – θ) = sin θ]

    (iv) cosec 31° – sec 59°
    cosec 31° – sec 59° = cosec 31° – cosec (90° – 59°) [∵ cosec (90° – θ) = sec θ]
    = cosec 31° – cosec 31° = 0

    See here for video explanation for this question😮👇

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