Substitute F = 95 into 95 = (9/5)C + 32. Subtracting 32 gives 63 = (9/5)C. Multiplying by 5/9 yields C = 63 × (5/9) = 35. The temperature is 35°C. Ganita Manjari Class 9 Maths part 2 Chapter 13 Solutions
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Substitute C = 30 into F = (9/5)C + 32. This yields F = (9/5)(30) + 32 = 9(6) + 32 = 54 + 32 = 86. Thus, the temperature is 86°F. NCERT Solution for Class 9 Ganita Manjari Part 2 ...
Using points (0, 32) and (10, 50), plot Celsius on the horizontal axis and Fahrenheit on the vertical axis. Drawing a straight line passing through these points produces the conversion graph. NCERT Solution for Class 9 Ganita Manjari Part 2 chapter ...
At the intersection with the vertical line x = 3, substitute x = 3 into y = 3x to obtain y = 3(3) = 9. Therefore, the point of intersection is (3, 9). Cbse released Class 9 Ganita Manjari Part 2 ...
Substitute x = 4 into y = 3x, which yields y = 3(4) = 12. Because the calculated value 12 does not equal the given y-coordinate 10, the point (4, 10) does not lie on the line. Ganita Manjari Class 9 ...