Let the EMFs of the two cells be E₁ and E₂. In series: E₁ + E₂ ∝ 8 m With one reversed: E₁ – E₂ ∝ 2 m Solving, (E₁ + E₂) / (E₁ – E₂) = 8/2 = 4.
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Total resistance is 6Ω, current is 5/3 A, potential drop across the wire is 5V and the potential gradient is 10 mV/cm. Correct answer: (b) 10 mV/cm. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions Session 2024-2025.
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