The minor sector area is (60/360) x π x r² = (1/6)πr². The triangle formed is equilateral with side r, giving area (√3/4)r². Subtracting yields segment area (1/6)πr² – (√3/4)r² = πr²(1/6 – √3/(4π)).
Home/Questions/Page 131
Discussion Forum Latest Questions
Kriti
Asked: In: Class 9 Maths
One blade cleans a sector of radius 28 cm and angle 120°: (120/360) x (22/7) x 28² = 2464/3 cm². With two blades, total cleaned area is 2 x (2464/3) = 4928/3 = 1642.67 cm².
Kriti
Asked: In: Class 9 Maths
Minor sector is (60/360) x 3.14 x 15² = 117.75 cm². Equilateral triangle area is (√3/4) x 15² = 97.31 cm². Minor segment is 117.75 – 97.31 = 20.44 cm². Major segment is 706.5 – 20.44 = 686.06 cm².
Kriti
Asked: In: Class 9 Maths
Radius is 10 cm. (i) Minor sector area is (90/360) x 3.14 x 10² = (1/4) x 314 = 78.5 cm². (ii) Major sector area is (270/360) x 3.14 x 10² = (3/4) x 314 = 235.5 cm².
Kriti
Asked: In: Class 9 Maths
In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².