Let the internal resistance be r and the balance lengths be I₁ = 2m, l₂ = 3m. Using the potentiometer equation: l₁/l₂ = R₁/R₂ Solving for r, we get 1 Ω. Answer: (a) 1 Ω.
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Let initial balance condition be: R₁ + 10/R₂ = 50/50 After removing 10 Ω, new balance condition: R₁/R₂ = 40/60 Solving for R₁, we get 40 Ω. Answer: (c) 40 Ω.
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