In Wheatston’e bridge, P = 2 Ω, Q = 2 Ω, R = 2 Ω and S = 3 Ω. The resistance with which S is to be shunted in order that the bridge may be balanced is :
For balance, p/Q = R/Seq . Given S = 3Ω, let shunt resistance be
x. Using Seq = 3x/3+x = 2Ω. solving gives x = 2Ω. Answer: (b) 2Ω.
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.
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