(i) Construct the Quadrilateral LIFT: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm (ii) Construct the Quadrilateral GOLD: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm (iii) Construct the Rhombus BEND: BN = 5.6 cm, DE = 6.5 cm

(i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm
To construct: A quadrilateral LIFT
Steps of construction:
(a) Draw a line segment LI = 4 cm.
(b) Taking radius 4.5 cm, draw an arc taking L as centre.
(c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.
(d) Join FI and FL.
(e) Draw another arc of radius 2.5 cm taking L as centre and 4 cm taking I as
centre which intersect at T.
(f) Join TF, Tl and TI.
It is the required quadrilateral LIFT.

Given: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm
To construct: A quadrilateral GOLD
Steps of construction:
(a) Draw a line segment OL = 7.5 cm
(b) Draw an arc of radius 5 cm taking L as centre and another arc of radius 10 cm taking O as centre which intersect the first arc point at D.
(c) Join LD and OD.
(d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G.
(e) Join GD and GO.
It is the required quadrilateral GOLD.

(iii) Given: BN = 5.6 cm, DE = 6.5 cm
To construct: A rhombus BEND.
Steps of construction:
(a) Draw DE = 6.5 cm.
(b) Draw perpendicular bisector of line segment DE.
(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.
(d) Join BE, BD as well as ND and NE.
It is the required rhombus BEND.

Class 8 Maths Chapter 4 Exercise 4.2 Solution in Video

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https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/