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(i) Construct the Quadrilateral LIFT: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm (ii) Construct the Quadrilateral GOLD: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm (iii) Construct the Rhombus BEND: BN = 5.6 cm, DE = 6.5 cm

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NCERT Solutions for Class 8 Mathematics Chapter 4
Important NCERT Questions
Practical Geometry Chapter 4 Exercise 4.2
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 1

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  1. (i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm
    To construct: A quadrilateral LIFT
    Steps of construction:
    (a) Draw a line segment LI = 4 cm.
    (b) Taking radius 4.5 cm, draw an arc taking L as centre.
    (c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.
    (d) Join FI and FL.
    (e) Draw another arc of radius 2.5 cm taking L as centre and 4 cm taking I as
    centre which intersect at T.
    (f) Join TF, Tl and TI.
    It is the required quadrilateral LIFT.

    Given: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm
    To construct: A quadrilateral GOLD
    Steps of construction:
    (a) Draw a line segment OL = 7.5 cm
    (b) Draw an arc of radius 5 cm taking L as centre and another arc of radius 10 cm taking O as centre which intersect the first arc point at D.
    (c) Join LD and OD.
    (d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G.
    (e) Join GD and GO.
    It is the required quadrilateral GOLD.

    (iii) Given: BN = 5.6 cm, DE = 6.5 cm
    To construct: A rhombus BEND.
    Steps of construction:
    (a) Draw DE = 6.5 cm.
    (b) Draw perpendicular bisector of line segment DE.
    (c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.
    (d) Join BE, BD as well as ND and NE.
    It is the required rhombus BEND.

    Class 8 Maths Chapter 4 Exercise 4.2 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

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