NCERT Solutions for Class 8 Mathematics Chapter 2
Important NCERT Questions
Linear Equations in one Variable Chapter 2 Exercise 2.4
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 7
Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹50 per meter and trouser material that costs him ₹90 per meter. For every 2 meters of the trouser material he buys 3 meters of the shirt material. He sells the materials at 12% and 10% respectively. His total sale is ₹36,000. How much trouser material did he buy?
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Let ratio between shirt material and trouser material be 3x : 2x
The cost of shirt material = 50X3x=150x
The selling price at 12% gain = 100+P%/10x c.p = 100+12/100x150x
= 112/100x150x=168x
The cost of trouser material = 90 X 2x =180x
The selling price at 12% gain = 100+P%/100 x C.P = 100+10/100x180x
= 110/100x180x = 198x
According to the question,
168x+198x=36,600
⇒ 366x=36600
⇒ x=36600/366 = 100 meters
Now, trouser material = 2x = 2 x 100 = 200 meters
Hence, Hasan bought 200 meters of the trouser material.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/