Varnu Singh
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A milkman sold two of his buffaloes for ₹ 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)

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NCERT Solutions for Class 8 Mathematics Chapter 8
Important NCERT Questions
Comparing Quantities Chapter 8 Exercise 8.2
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 7

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1 Answer

  1. S.P. of each buffalo = ₹ 20,000
    S.P. of two buffaloes = ₹ 20,000 x 2 = ₹ 40,000
    One buffalo is sold at 5% gain.
    Let C.P. be ₹ 100, then S.P. = 100 + 5 = ₹105
    ∵ When S.P. is ₹ 105, then C.P. = ₹ 100
    ∴ When S.P. is ₹ 1, then C.P. = 100/105
    ∴ When S.P. is ₹ 20,000, then C.P. = 100/105 x 20000 = ₹ 19,047.62
    Another buffalo is sold at 10% loss.
    Let C.P. be ₹ 100, then S.P. = 100 – 10 = ₹ 90
    ∵ When S.P. is ₹ 90, then C.P. = ₹ 100
    ∴ When S.P. is ₹ 1, then C.P. = 100/90
    ∴ When S.P. is ₹ 20,000, then C.P. = 100/90×20000 = ₹ 22,222.22
    Total C.P. = ₹ 19,047.62 + ₹ 22,222.22 = ₹ 41,269.84
    Since C.P. > S.P. Therefore here it is loss.
    Loss = C.P. – S.P. = ₹ 41,269.84 – ₹ 40,000.00 = ₹ 1,269.84

    Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video

    Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video

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