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What is the force between two small charged spheres having charges of 2 × 10⁻⁷ C and 3 × 10 ⁻⁷ C placed 30 cm apart in air?

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Class-12th Physics, CBSE and UP Board
Electric Charges and Fields,
Chapter-1, Exercise -1, Q-1.1
NCERT Solutions for Class 12th Physics

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1 Answer

  1. Since force between two charges q1 and q2 separated by a distance of r is given by expression:

    F=1 /4πε0   x   q1q2/r²

    Where ε0   =Permittivity of free space and value of

    1 /4πε0 =9 X 109 Nm 2C⁻²

    and given

    Charge on the first sphere, q1= 2 x 10-7 C Charge on the second sphere,

    q2= 3 x 10-7 C Distance between the spheres, r = 30 cm = 0.3 m

    Therefore

    F=9 x 10x (2 x 10-7 x3 x 10-7 )/(0.3 )²

    F=6 X 10⁻ ³ N

    Hence, force between the two small charged spheres is 6 x 10-3 N. The charges are of same nature. Hence, force between them will be repulsive.

     

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