We transform 105 into 100 + 5 and apply the identity with a = 100 and b = 5. Adding the squared values to the middle cross-product gives the correct total.
Home/exploring algebraic identities: class 9 (ganita manjari)/Page 5
Discussion Forum Latest Questions
Ayushree
Asked: In: Class 9 Maths
We substitute a = 1/x and b = 1/y into the identity. Finding the squares of these fractional variables and combining their cross-product gives the final simplified rational terms.
Ayushree
Asked: In: Class 9 Maths
We use the identity with a = 7/5 x and b = 3/2 y. Squaring the fractional coefficients and multiplying two with both terms yields the expanded expression with simplified fraction terms.