Circumference 2 x (22/7) x r = 66 gives radius r = 21/2 cm. The area of the quadrant is (1/4) x π x r² = (1/4) x (22/7) x (21/2)² = 693/8 = 86.625 cm².
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Wheel circumference is π x d = (22/7) x 60 = 1320/7 cm (approx 1.886 m). For 100 rotations, total distance is 100 x (1320/7) = 132000/7 cm ≈ 18857.14 cm = 188.57 m.
Way 1: Since 7² + 24² = 49 + 576 = 625 = 25², it is a right triangle, so Area = (1/2) x 7 x 24 = 84 cm². Way 2: Semi-perimeter s = 28 cm; Heron’s formula yields ...
Sides are 2x, 3x, 4x with sum 9x = 45, giving sides 10 cm, 15 cm, 20 cm. Semi-perimeter s = 22.5 cm. By Heron’s formula, area = √(22.5 x 12.5 x 7.5 x 2.5) = (75/4)√15 cm² (approx 72.62 ...
Other leg is (2 x 54) / 12 = 9 cm. Hypotenuse is √(12² + 9²) = √(144 + 81) = √225 = 15 cm. Perimeter = 12 + 9 + 15 = 36 cm.