New radius is 1.1r, making squared radius 1.21r². For unchanged volume, the new height must be h / 1.21 ≈ 0.8264h. Thus, height decreases by approximately 17.36%, meaning x ≈ 17.36 or 2100/121%. Class 9 Chapter 14 Math of Space Surface ...
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Here, a₁/a₂ = 6/2 = 3, b₁/b₂ = -3/(-1) = 3 and c₁/c₂ = 10/9. Since a₁/a₂ = b₁/b₂ ≠ c₁/c₂, the lines are parallel and possess no common solution. Cbse released Class 9 Ganita Manjari Part 2 book Chapter 13 ...
The ratios are a₁/a₂ = 9/18 = 1/2, b₁/b₂ = 3/6 = 1/2 and c₁/c₂ = 12/24 = 1/2. Since a₁/a₂ = b₁/b₂ = c₁/c₂, the lines are coincident with infinitely many solutions. Cbse released Class 9 Ganita Manjari Part 2 ...
Here, a₁/a₂ = 5/7 and b₁/b₂ = -4/6 = -2/3. Since a₁/a₂ ≠ b₁/b₂, the system possesses a unique solution, meaning the lines intersect at a single point. Class 9 Maths (Ganita Manjari part two) Chapter 13 questions answer Class 9 ...
Let boys be x and girls y. The equations are x + y = 10 and y – x = 4. Graphing both lines reveals their unique intersection point at (3, 7). Thus, 3 boys and 7 girls participated. Ganita Manjari ...