Inner track perimeter = 4 x 100 = 400 m. Outer track perimeter = 4 x 150 = 600 m. Starting positions should align so their distances equal 350 m. Use proportions to determine the start points. class 6 Mathematics Textbook ...
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The inner track perimeter is 2 x (60 + 30) = 180 m. Toshi runs 7 rounds. Total distance = 7 x 180 = 1260 m. Toshi ran farther than Akshi’s 1100 m. class 6 Mathematics Textbook Chapter 6 question answer class ...
The outer track perimeter is 2 x (70 + 40) = 220 m. Akshi runs 5 rounds. Total distance covered = 5 x 220 = 1100 m. class 6 Mathematics Textbook Chapter 6 question answer class 6 Mathematics Chapter 6 Perimeter and ...
Outer track perimeter = 2 x (70 + 40) = 220 m. Distance by Akshi = 5 x 220 = 1100 m. Inner track perimeter = 2 x (60 + 30) = 180 m. Distance by Toshi = 7 x ...
The perimeter of the field is 2 x (230 + 160) = 2 x 390 = 780 m. For 3 rounds, total rope needed is 3 x 780 = 2340 m. class 6 Mathematics Textbook Chapter 6 question answer class 6 Mathematics ...
A square’s perimeter is 4 x side. Using the formula: 36 = 4 x side, side = 36 รท 4 = 9 cm. Each side of the square is 9 cm. Class 6 NCERT Ganita Prakash Chapter 6 Perimeter and Area class ...
The perimeter is 2 x (150 + 120) = 2 x 270 = 540 m. Total cost = 540 x 40 = 21600. The fencing will cost 21600 rupees. Class 6 NCERT Ganita Prakash Chapter 6 Perimeter and Area class 6 Mathematics ...
The perimeter is the sum of all sides. Using the formula: 55 = 20 + 14 + third side. Solving gives third side = 55 – 34 = 21 cm. Class 6 NCERT Ganita Prakash Chapter 6 Perimeter and Area class 6 ...
Perimeter of the rectangle is 2 x (5 + 3) = 16 cm. When bent into a square, the perimeter remains the same. Length of one side = 16 รท 4 = 4 cm. Class 6 NCERT Ganita Prakash Chapter 6 ...
The formula for the perimeter is 2 x (length + breadth). Substituting values: 14 = 2 x (length + 2). Simplifying gives length = 5 cm. Class 6 Mathematics Chapter 6 Perimeter and Area question answer Class 6 NCERT Ganita Prakash Chapter ...