The two numbers are 25 and 400. Their product 25 × 400 = 10000 satisfies the condition. Both numbers end in digits other than 0, meeting the given requirements. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics Textbook ...
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Only 5600, 6000, and 77622160 are divisible by all. Divisibility by 2, 4, 5, 8, and 10 requires multiples of their least common multiple (LCM), 40. These numbers meet the criteria. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 ...
The two numbers are 8 and 5. Divisibility by 8 confirms divisibility by 2 and 4. Divisibility by 5 ensures divisibility by 10. Hence, checking these two guarantees divisibility by all. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 ...
Remainders obtained when each of the following numbers is divided by 10, 5, 2. 78: Rem. by 10: 8, by 5: 3, by 2: 0 99: Rem. by 10: 9, by 5: 4, by 2: 1 173: Rem. by 10: 3, by 5: ...
The game says ‘idli-vada’ for common multiples of 3 and 5. These are: 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Thus, the 10th instance is at 150. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics Chapter ...