Horizontal component BH = B cosδ. Given: BH 0.2G, B = 0.4G So, cosδ = 0.2/0.4 = 0.5 δ = cos⁻¹ (0.5) = 60°. Answer: (C) 60°.
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In ferromagnetic materials, as the magnetizing field increases, permeability initially increases, reaches a maximum and then decreases due to magnetic saturation. So, permeability does not keep increasing. Correct answer: (A) decreases.
Let voltmeter resistance be R. Since scale becomes 50 times larger, current reduces by 50 times. So, total resistance becomes 50R. Given: 50R = R + 980 ⇒ 49R = 980 ⇒ R = 20 Ω. Answer: (B) 20 Ω.
(A) is correct. If only 1/34 of total current passes through the galvanometer, then shunt resistance Rs = Rg/33 = 3663/33 ≈ 111Ω, which is closest to 100 Ω. So, option (A) is correct.
(B) is correct. To convert a galvanometer into an ammeter with a 10 A range, a small shunt resistance is added in parallel. Using Rs = Ig⋅G/I−Ig’ we get Rs ≈ 0.01Ω.