Four times the focal length of the lens. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
Category: Class 12 Physics
NCERT Solutions for Class 12 Physics updated for CBSE academic session 2021-2022.
Tiwari Academy Discussion Latest Questions
Virtual image formed by a convex lens is erect and magnified but the virtual image formed by a concave lens is always erect and diminished one. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
P = P₁ + P2 = (+ 6 D) + (-2D) = + 4 D Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
When tha concave lens of refractive index 1.5 (ng = 1.5) is immersed in a midium of refractive index 1.65 (nm = 1.65), the lens begins to behave as a converging (convex) lens. Class 12 Physics Chapter 9 Ray Optics ...
Refractive index of liquid should be 1.5. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D Hence, f = 1/p = – 1/2 m = -50 cm. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
The focal length of the given convex lens is 20 cm. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
Let focal length of converging lens f₁ = + f and focal length of diverging lens f₂ = -f. If focal length of combination be feq, then 1/feq = 1/f1 + 1/f2 = 1/(+f) + 1/(-f) = 0 feq = ...
The lens will now behave as a converging lens because its new refractive index w.r.t. water is less than one. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
The lens will disappear and there will be no converging or diverging action of the lens. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.