0.4 ÷ 2 = 4/10 x 1/2 = 2/10 =0.2 Class 7 Maths Chapter 2 Exercise 2.7 Question 1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
∵ In one litre, a two-wheeler covers a distance = 55.3 km ∴ In 10 litres, a two- wheeler covers a distance = 55.3 x 10 = 553.0 km Thus, 553 km distance will be covered by it in 10 litres of petrol. Class 7 Maths Chapter 2 Exercise 2.6 Question 4, 5 for more answers vist to: https://www.tiwariacademyRead more
∵ In one litre, a two-wheeler covers a distance = 55.3 km
∴ In 10 litres, a two- wheeler covers a distance = 55.3 x 10 = 553.0 km
Thus, 553 km distance will be covered by it in 10 litres of petrol.
Class 7 Maths Chapter 2 Exercise 2.6 Question 4, 5
Given: Length of rectangle = 5.7 cm and Breadth of rectangle = 3 cm Area of rectangle = Length x Breadth = 5.7 x 3 = 17.1 cm² Thus, the area of rectangle is 17.1 cm². Class 7 Maths Chapter 2 Exercise 2.6 Question 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7Read more
Given: Length of rectangle = 5.7 cm and
Breadth of rectangle = 3 cm
Area of rectangle = Length x Breadth = 5.7 x 3 = 17.1 cm²
Thus, the area of rectangle is 17.1 cm².
Find: 0.4 ÷ 2
0.4 ÷ 2 = 4/10 x 1/2 = 2/10 =0.2 Class 7 Maths Chapter 2 Exercise 2.7 Question 1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
0.4 ÷ 2 = 4/10 x 1/2 = 2/10 =0.2
Class 7 Maths Chapter 2 Exercise 2.7 Question 1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
Find: (i) 2.5 x 0.3 (ii) 0.1 x 51.7 (iii) 0.2 x 316.8 (iv) 1.3 x 3.1 (v) 0.5 x 0.05 (vi) 11.2 x 0.15 (vii) 1.07 x 0.02 (viii) 10.05 x 1.05 (ix) 101.01 x 0.01 (x) 100.01 x 1.1
(i) 2.5 x 0.3 = 0.75 (ii) 0.1 x 51.7 = 5.17 (iii) 0.2 x 316.8 = 63.36 (iv) 1.3 x 3.1 = 4.03 (v) 0.5 x 0.05 = 0.025 (vi) 11.2 x 0.15 = 1.680 (vii) 1.07 x 0.02 = 0.0214 (viii) 10.05 x 1.05 = 10.5525 (ix) 101.01 x 0.01 = 1.0101 (x) 100.01 x 1.1 = 110.11 Class 7 Maths Chapter 2 Exercise 2.6 Question 4,Read more
(i) 2.5 x 0.3 = 0.75 (ii) 0.1 x 51.7 = 5.17
(iii) 0.2 x 316.8 = 63.36 (iv) 1.3 x 3.1 = 4.03
(v) 0.5 x 0.05 = 0.025 (vi) 11.2 x 0.15 = 1.680
(vii) 1.07 x 0.02 = 0.0214 (viii) 10.05 x 1.05 = 10.5525
(ix) 101.01 x 0.01 = 1.0101 (x) 100.01 x 1.1 = 110.11
Class 7 Maths Chapter 2 Exercise 2.6 Question 4, 5
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?
∵ In one litre, a two-wheeler covers a distance = 55.3 km ∴ In 10 litres, a two- wheeler covers a distance = 55.3 x 10 = 553.0 km Thus, 553 km distance will be covered by it in 10 litres of petrol. Class 7 Maths Chapter 2 Exercise 2.6 Question 4, 5 for more answers vist to: https://www.tiwariacademyRead more
∵ In one litre, a two-wheeler covers a distance = 55.3 km
∴ In 10 litres, a two- wheeler covers a distance = 55.3 x 10 = 553.0 km
Thus, 553 km distance will be covered by it in 10 litres of petrol.
Class 7 Maths Chapter 2 Exercise 2.6 Question 4, 5
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
Find: (i) 1.3 x 10 (ii) 36.8 x 10 (iii) 153.7 x 10 (iv) 168.07 x 10 (v) 31.1 x 100 (vi) 156.1 x 100 (vii) 3.62 x 100 (viii) 43.07 x 100 (ix) 0.5 x 10 (x) 0.08 x 10 (xi) 0.9 x 100 (xii) 0.03 x 1000
(i) 1.3 x 10 = 13.0 (ii) 36.8 x 10 = 368.0 (iii) 153.7 x 10 = 1537.0 (iv) 168.07 x 10 = 1680.7 (v) 31.1 x 100 = 3110.0 (vi) 156.1 x 100 = 15610.0 (vii) 3.62 x 100 = 362.0 (viii) 43.07 x 100 = 4307.0 (ix) 0.5 x 10 = 5.0 (x) 0.08 x 10 = 0.80 (xi) 0.9 x 100 = 90.0 (xii) 0.03 x 1000 = 30.0 Class 7 MathsRead more
(i) 1.3 x 10 = 13.0 (ii) 36.8 x 10 = 368.0
(iii) 153.7 x 10 = 1537.0 (iv) 168.07 x 10 = 1680.7
(v) 31.1 x 100 = 3110.0 (vi) 156.1 x 100 = 15610.0
(vii) 3.62 x 100 = 362.0 (viii) 43.07 x 100 = 4307.0
(ix) 0.5 x 10 = 5.0 (x) 0.08 x 10 = 0.80
(xi) 0.9 x 100 = 90.0 (xii) 0.03 x 1000 = 30.0
Class 7 Maths Chapter 2 Exercise 2.6 Question 1, 2, 3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/
Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.
Given: Length of rectangle = 5.7 cm and Breadth of rectangle = 3 cm Area of rectangle = Length x Breadth = 5.7 x 3 = 17.1 cm² Thus, the area of rectangle is 17.1 cm². Class 7 Maths Chapter 2 Exercise 2.6 Question 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7Read more
Given: Length of rectangle = 5.7 cm and
Breadth of rectangle = 3 cm
Area of rectangle = Length x Breadth = 5.7 x 3 = 17.1 cm²
Thus, the area of rectangle is 17.1 cm².
Class 7 Maths Chapter 2 Exercise 2.6 Question 1, 2, 3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/