1. a. Walking at 5 kilometers per hour, it takes approximately 24 minutes to reach a favorite place 2 kilometers away (2 ÷ 5 × 60 = 24 minutes). Travel time varies with walking pace and terrain—hills or uneven paths may slow progress, while faster walking reduces it. b. The distance between GandhinagarRead more

    a. Walking at 5 kilometers per hour, it takes approximately 24 minutes to reach a favorite place 2 kilometers away (2 ÷ 5 × 60 = 24 minutes). Travel time varies with walking pace and terrain—hills or uneven paths may slow progress, while faster walking reduces it.

    b. The distance between Gandhinagar (Gujarat) and Jaipur (Rajasthan) is roughly 650 kilometers. Walking at an average speed of 5 km/h, it would take around 130 hours, or approximately 5 days and 10 hours. It would be kept as records by societies.

    c. The distance between Kanyakumari (southernmost) and Kashmir (northernmost) is approximately 3,200 kilometers. Walking at an average speed of 5 km/h would require roughly 640 hours, or about 26 days and 16 hours. This journey help students grasp the scale of geographical distances and reflect on the daily challenges and realities of historical travel. In other words it would be called insanity.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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  2. Estimate the number of books in your school library by considering rows, shelves, and average books per shelf. For example, if there are 50 shelves and each holds 40 books, the total is about 2,000 books. Ask your classmates to break down the problem, comparing methods of counting and estimation. ThRead more

    Estimate the number of books in your school library by considering rows, shelves, and average books per shelf. For example, if there are 50 shelves and each holds 40 books, the total is about 2,000 books. Ask your classmates to break down the problem, comparing methods of counting and estimation. This activity encourages analytical thinking, pattern recognition, and practical application of mathematical principles. Discussing approaches and sharing estimates fosters deeper understanding of the topic.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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  3. The supercell in the given grid is 62,871. By swapping the digits 2 and 8, the number changes to 68,271. This alteration results in four supercells: 39,344, 68,271, 50,319, and 45,306. Supercells are numbers greater than all their immediate neighbors. The swap successfully increases the number of suRead more

    The supercell in the given grid is 62,871. By swapping the digits 2 and 8, the number changes to 68,271. This alteration results in four supercells: 39,344, 68,271, 50,319, and 45,306. Supercells are numbers greater than all their immediate neighbors. The swap successfully increases the number of supercells to four, fulfilling the given condition and maintaining the logical structure of the grid.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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  4. The Kaprekar constant is achieved by rearranging the digits of your birth year to form the largest and smallest numbers, then subtracting the smaller from the larger. Repeating this process typically takes six to seven iterations to reach 6174. For example, if your birth year is 1990, perform the stRead more

    The Kaprekar constant is achieved by rearranging the digits of your birth year to form the largest and smallest numbers, then subtracting the smaller from the larger. Repeating this process typically takes six to seven iterations to reach 6174. For example, if your birth year is 1990, perform the steps systematically to see how many rounds it takes for your specific case.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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  5. Within the range 35,000 to 75,000, only numbers with all odd digits qualify. The largest is 75,999, formed using the highest odd digits. The smallest is 35,135, as it uses the smallest odd digits. The number closest to 50,000 is 49,975. These numbers are derived logically by alternating odd digits tRead more

    Within the range 35,000 to 75,000, only numbers with all odd digits qualify. The largest is 75,999, formed using the highest odd digits. The smallest is 35,135, as it uses the smallest odd digits. The number closest to 50,000 is 49,975. These numbers are derived logically by alternating odd digits to form numbers that meet the given conditions while being close to the limits.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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