Students play a vital role in building transparent and accountable societies: Promoting Environmental Responsibility: Leading campus waste segregation drives, saving municipal water and organizing neighborhood tree-planting campaigns. Advancing Digital Literacy: Teaching domestic staff, elderly relaRead more
Students play a vital role in building transparent and accountable societies:
Promoting Environmental Responsibility: Leading campus waste segregation drives, saving municipal water and organizing neighborhood tree-planting campaigns.
Advancing Digital Literacy: Teaching domestic staff, elderly relatives and underprivileged communities how to access online government welfare and education portals.
Respecting the Rule of Law: Following road safety rules, avoiding littering in public areas and protecting cultural monuments from defacement.
Participating in Student Governance: Engaging honestly in school elections, mock youth parliaments and student councils to cultivate democratic values.
Community Service and Vigilance: Volunteering in local sanitation drives, reporting municipal infrastructure damage and raising awareness about civic rights and community duties.
For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 4 Governance and Public Policy Question Answer (2026-27)
Sheetal Devi is shown engaging in archery using a modified technique since she lacks arms. She draws the bowstring utilizing her foot, leg and chin with sheer focus and determination. Her posture reveals intense concentration, strength and remarkable physical balance. This image clearly showcases hoRead more
Sheetal Devi is shown engaging in archery using a modified technique since she lacks arms. She draws the bowstring utilizing her foot, leg and chin with sheer focus and determination. Her posture reveals intense concentration, strength and remarkable physical balance. This image clearly showcases how human perseverance and innovative effort can overcome severe physical boundaries, transforming adversity into world-class athletic excellence on the global sporting stage.
For more NCERT Solutions of Class 9 English Kaveri Chapter 5 The World of Limitless Possibilities Question Answer (2026-27)
Let k consecutive natural numbers start at a, where k >= 2. Their sum is: S = (k / 2) x [2a + (k - 1)] = 100 k(2a + k - 1) = 200. Here, one factor must be odd and the other even. The odd factors of 200 are 1, 5 and 25. For k = 5: 5(2a + 4) = 200 2a + 4 = 40 2a = 36, so a = 18. For k = 25: 25(2a +Read more
Let k consecutive natural numbers start at a, where k >= 2.
Their sum is:
S = (k / 2) x [2a + (k – 1)] = 100
k(2a + k – 1) = 200.
Here, one factor must be odd and the other even. The odd factors of 200 are 1, 5 and 25.
For k = 5:
5(2a + 4) = 200
2a + 4 = 40
2a = 36, so a = 18.
For k = 25:
25(2a + 24) = 200 gives 2a + 24 = 8, so a = -8 (not natural).
Thus, the only way is 18 + 19 + 20 + 21 + 22.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
Let the first term be a and common difference be d. Given: t7 - t5 = 12 (a + 6d) - (a + 4d) = 12 2d = 12 d = 6. Also, the third term is 16: t3 = a + 2d = 16 a + 2 x 6 = 16 a + 12 = 16 a = 4. With first term a = 4 and common difference d = 6, the terms are: First term = 4 Second term = 4 + 6 =Read more
Let the first term be a and common difference be d.
Given:
t7 – t5 = 12
(a + 6d) – (a + 4d) = 12
2d = 12
d = 6.
Also, the third term is 16:
t3 = a + 2d = 16
a + 2 x 6 = 16
a + 12 = 16
a = 4.
With first term a = 4 and common difference d = 6, the terms are:
First term = 4
Second term = 4 + 6 = 10
Third term = 10 + 6 = 16
Fourth term = 16 + 6 = 22.
Thus, the arithmetic progression is 4, 10, 16, 22, ….
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
Let a be the first term and d be the common difference. Given: 11th term: t11 = a + 10d = 38 16th term: t16 = a + 15d = 73 Subtracting the first equation from the second: (a + 15d) - (a + 10d) = 73 - 38 5d = 35 d = 7. Substituting d = 7 into the first equation: a + 10 x 7 = 38 a + 70 = 38 a = 38 - 7Read more
Let a be the first term and d be the common difference.
Given:
11th term: t11 = a + 10d = 38
16th term: t16 = a + 15d = 73
Subtracting the first equation from the second:
(a + 15d) – (a + 10d) = 73 – 38
5d = 35
d = 7.
Substituting d = 7 into the first equation:
a + 10 x 7 = 38
a + 70 = 38
a = 38 – 70 = -32.
Now, finding the 31st term:
t31 = a + 30d = -32 + 30 x 7 = -32 + 210 = 178.
Hence, the 31st term is 178.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
Do you think students can contribute to good governance? Write a short note describing any five ways in which students can become more responsible and active citizens.
Students play a vital role in building transparent and accountable societies: Promoting Environmental Responsibility: Leading campus waste segregation drives, saving municipal water and organizing neighborhood tree-planting campaigns. Advancing Digital Literacy: Teaching domestic staff, elderly relaRead more
Students play a vital role in building transparent and accountable societies:
For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 4 Governance and Public Policy Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/part-2-chapter-4/
See lessLook at the picture carefully and share your observations with your classmates and teacher.
Sheetal Devi is shown engaging in archery using a modified technique since she lacks arms. She draws the bowstring utilizing her foot, leg and chin with sheer focus and determination. Her posture reveals intense concentration, strength and remarkable physical balance. This image clearly showcases hoRead more
Sheetal Devi is shown engaging in archery using a modified technique since she lacks arms. She draws the bowstring utilizing her foot, leg and chin with sheer focus and determination. Her posture reveals intense concentration, strength and remarkable physical balance. This image clearly showcases how human perseverance and innovative effort can overcome severe physical boundaries, transforming adversity into world-class athletic excellence on the global sporting stage.
For more NCERT Solutions of Class 9 English Kaveri Chapter 5 The World of Limitless Possibilities Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/english/kaveri-chapter-5/
See lessFind all possible ways of expressing 100 as the sum of consecutive natural numbers.
Let k consecutive natural numbers start at a, where k >= 2. Their sum is: S = (k / 2) x [2a + (k - 1)] = 100 k(2a + k - 1) = 200. Here, one factor must be odd and the other even. The odd factors of 200 are 1, 5 and 25. For k = 5: 5(2a + 4) = 200 2a + 4 = 40 2a = 36, so a = 18. For k = 25: 25(2a +Read more
Let k consecutive natural numbers start at a, where k >= 2.
Their sum is:
S = (k / 2) x [2a + (k – 1)] = 100
k(2a + k – 1) = 200.
Here, one factor must be odd and the other even. The odd factors of 200 are 1, 5 and 25.
For k = 5:
5(2a + 4) = 200
2a + 4 = 40
2a = 36, so a = 18.
For k = 25:
25(2a + 24) = 200 gives 2a + 24 = 8, so a = -8 (not natural).
Thus, the only way is 18 + 19 + 20 + 21 + 22.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/
See lessDetermine the AP whose third term is 16 and whose 7th term exceeds the 5th term by 12.
Let the first term be a and common difference be d. Given: t7 - t5 = 12 (a + 6d) - (a + 4d) = 12 2d = 12 d = 6. Also, the third term is 16: t3 = a + 2d = 16 a + 2 x 6 = 16 a + 12 = 16 a = 4. With first term a = 4 and common difference d = 6, the terms are: First term = 4 Second term = 4 + 6 =Read more
Let the first term be a and common difference be d.
Given:
t7 – t5 = 12
(a + 6d) – (a + 4d) = 12
2d = 12
d = 6.
Also, the third term is 16:
t3 = a + 2d = 16
a + 2 x 6 = 16
a + 12 = 16
a = 4.
With first term a = 4 and common difference d = 6, the terms are:
First term = 4
Second term = 4 + 6 = 10
Third term = 10 + 6 = 16
Fourth term = 16 + 6 = 22.
Thus, the arithmetic progression is 4, 10, 16, 22, ….
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/
See lessFind the 31st term of an AP whose 11th term is 38 and 16th term is 73.
Let a be the first term and d be the common difference. Given: 11th term: t11 = a + 10d = 38 16th term: t16 = a + 15d = 73 Subtracting the first equation from the second: (a + 15d) - (a + 10d) = 73 - 38 5d = 35 d = 7. Substituting d = 7 into the first equation: a + 10 x 7 = 38 a + 70 = 38 a = 38 - 7Read more
Let a be the first term and d be the common difference.
Given:
11th term: t11 = a + 10d = 38
16th term: t16 = a + 15d = 73
Subtracting the first equation from the second:
(a + 15d) – (a + 10d) = 73 – 38
5d = 35
d = 7.
Substituting d = 7 into the first equation:
a + 10 x 7 = 38
a + 70 = 38
a = 38 – 70 = -32.
Now, finding the 31st term:
t31 = a + 30d = -32 + 30 x 7 = -32 + 210 = 178.
Hence, the 31st term is 178.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/
See less