Thickness of one book = 20 mm Thickness of 5 books = 20 x 5 = 100 mm Thickness of one paper = 0.016 mm Thickness of 5 papers = 0.016 x 5 = 0.08 mm Total thickness of a stack = 100 + 0.08 = 100.08 mm = 100.08 x 10²/10² = 100.08x10² mm Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for moreRead more
Thickness of one book = 20 mm
Thickness of 5 books = 20 x 5 = 100 mm
Thickness of one paper = 0.016 mm
Thickness of 5 papers = 0.016 x 5 = 0.08 mm
Total thickness of a stack = 100 + 0.08
= 100.08 mm
= 100.08 x 10²/10² = 100.08×10² mm
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
1 micron = 1/1000000 = 1/10⁶ = 1x10⁻⁶ m Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
1 micron = 1/1000000 = 1/10⁶ = 1×10⁻⁶ m
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
3.02×10⁻⁶ = 3.02/10⁶ = 0.00000302 Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
3.02×10⁻⁶ = 3.02/10⁶ = 0.00000302
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
0.0000000000085 = 0.0000000000085 x 10¹²/10¹² = 8.5x10⁻¹² Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
0.0000000000085 = 0.0000000000085 x 10¹²/10¹² = 8.5×10⁻¹²
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
25xt⁻⁴ / 5⁻³x10xt⁻⁸ (t≠0) = 5²xt⁻⁴/5⁻³x5x2xt⁻⁸ = 5²⁻(⁻³)⁻¹xt⁻⁴⁻⁸/2 [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5²⁺³⁻¹xt⁻⁴⁺⁸/2 = 5⁴xt⁴/2 = 625/2 t⁴ Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
In a stack there are 5 books each of thickness 20 mm and 5 paper sheets each of thickness 0.016 mm. What is the total thickness of the stack?
Thickness of one book = 20 mm Thickness of 5 books = 20 x 5 = 100 mm Thickness of one paper = 0.016 mm Thickness of 5 papers = 0.016 x 5 = 0.08 mm Total thickness of a stack = 100 + 0.08 = 100.08 mm = 100.08 x 10²/10² = 100.08x10² mm Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for moreRead more
Thickness of one book = 20 mm
Thickness of 5 books = 20 x 5 = 100 mm
Thickness of one paper = 0.016 mm
Thickness of 5 papers = 0.016 x 5 = 0.08 mm
Total thickness of a stack = 100 + 0.08
= 100.08 mm
= 100.08 x 10²/10² = 100.08×10² mm
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Express the number appearing in the following statements in standard form: 1 micron is equal to 1/1000000 m.
1 micron = 1/1000000 = 1/10⁶ = 1x10⁻⁶ m Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
1 micron = 1/1000000 = 1/10⁶ = 1×10⁻⁶ m
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Express the following numbers in usual form: 3.02×10⁻⁶
3.02×10⁻⁶ = 3.02/10⁶ = 0.00000302 Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
3.02×10⁻⁶ = 3.02/10⁶ = 0.00000302
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Express the following numbers in standard form: 0.0000000000085
0.0000000000085 = 0.0000000000085 x 10¹²/10¹² = 8.5x10⁻¹² Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
0.0000000000085 = 0.0000000000085 x 10¹²/10¹² = 8.5×10⁻¹²
Class 8 Maths Chapter 11 Exercise 12.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Simplify: 25xt⁻⁴ / 5⁻³x10xt⁻⁸ (t≠0)
25xt⁻⁴ / 5⁻³x10xt⁻⁸ (t≠0) = 5²xt⁻⁴/5⁻³x5x2xt⁻⁸ = 5²⁻(⁻³)⁻¹xt⁻⁴⁻⁸/2 [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5²⁺³⁻¹xt⁻⁴⁺⁸/2 = 5⁴xt⁴/2 = 625/2 t⁴ Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
25xt⁻⁴ / 5⁻³x10xt⁻⁸ (t≠0) = 5²xt⁻⁴/5⁻³x5x2xt⁻⁸ = 5²⁻(⁻³)⁻¹xt⁻⁴⁻⁸/2 [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ]
= 5²⁺³⁻¹xt⁻⁴⁺⁸/2 = 5⁴xt⁴/2 = 625/2 t⁴
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/