(5/8)⁻⁷ x (8/5)⁻⁴ = 5⁻⁷/8⁻⁷ x 8⁻⁴⁻(⁻⁷) [∵ (a/b)ᵐ =aᵐ/bᵐ] = 5⁻⁷⁻(⁻⁴) x 8⁻⁴⁻⁷ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5⁻⁷⁺⁴x8⁻⁴⁺⁷ = 5⁻³x8³ =8³/8³ [∵ a⁻ᵐ=1/aᵐ] = 512/125 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(5/8)⁻⁷ x (8/5)⁻⁴ = 5⁻⁷/8⁻⁷ x 8⁻⁴⁻(⁻⁷) [∵ (a/b)ᵐ =aᵐ/bᵐ]
= 5⁻⁷⁻(⁻⁴) x 8⁻⁴⁻⁷ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ]
= 5⁻⁷⁺⁴x8⁻⁴⁺⁷ = 5⁻³x8³ =8³/8³ [∵ a⁻ᵐ=1/aᵐ]
= 512/125
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
5ᵐ÷5⁻³=5⁵ ⇒ 5ᵐ⁻(⁻³)= 5⁵ [∵aᵐ÷aₙ=aᵐ⁻ᵐ] ⇒ 5ᵐ⁺³ =5⁵ Comparing exponents both sides, we get ⇒ m+3=5 ⇒ m=5-3 ⇒ m=2 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
5ᵐ÷5⁻³=5⁵
⇒ 5ᵐ⁻(⁻³)= 5⁵ [∵aᵐ÷aₙ=aᵐ⁻ᵐ]
⇒ 5ᵐ⁺³ =5⁵
Comparing exponents both sides, we get
⇒ m+3=5
⇒ m=5-3
⇒ m=2
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
8⁻¹ x5³/2⁻⁴ = (2³)⁻¹ x 5³/2⁻⁴ = 2⁻³x5³/2⁻⁴ [∵(aᵐ)ⁿ=aᵐˣⁿ] = 2⁻³(⁻⁴)x5³= 2⁻³⁺⁴x5³ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 2x125=250 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(3⁰+4⁻¹)x2² = (1+1/4)x2² [∵ a⁻ᵐ =1/aᵐ] = (4+1/4) x 2²=5/4x2²=5/2²x2² = 5x2²⁻² [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5x2⁰ = 5x1 = 5 [∵ a⁰=1] Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(-4)⁵ ÷(-4)⁸ = (-4)⁵⁻⁸ = (-4)⁻³ = 1/(-4)⁸ Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(-4)⁵ ÷(-4)⁸ = (-4)⁵⁻⁸
= (-4)⁻³ = 1/(-4)⁸
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
Evaluate: (5/8)⁻⁷ x (8/5)⁻⁴
(5/8)⁻⁷ x (8/5)⁻⁴ = 5⁻⁷/8⁻⁷ x 8⁻⁴⁻(⁻⁷) [∵ (a/b)ᵐ =aᵐ/bᵐ] = 5⁻⁷⁻(⁻⁴) x 8⁻⁴⁻⁷ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5⁻⁷⁺⁴x8⁻⁴⁺⁷ = 5⁻³x8³ =8³/8³ [∵ a⁻ᵐ=1/aᵐ] = 512/125 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(5/8)⁻⁷ x (8/5)⁻⁴ = 5⁻⁷/8⁻⁷ x 8⁻⁴⁻(⁻⁷) [∵ (a/b)ᵐ =aᵐ/bᵐ]
= 5⁻⁷⁻(⁻⁴) x 8⁻⁴⁻⁷ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ]
= 5⁻⁷⁺⁴x8⁻⁴⁺⁷ = 5⁻³x8³ =8³/8³ [∵ a⁻ᵐ=1/aᵐ]
= 512/125
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Find the value of m for which 5ᵐ÷5⁻⁻³=5⁵
5ᵐ÷5⁻³=5⁵ ⇒ 5ᵐ⁻(⁻³)= 5⁵ [∵aᵐ÷aₙ=aᵐ⁻ᵐ] ⇒ 5ᵐ⁺³ =5⁵ Comparing exponents both sides, we get ⇒ m+3=5 ⇒ m=5-3 ⇒ m=2 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
5ᵐ÷5⁻³=5⁵
⇒ 5ᵐ⁻(⁻³)= 5⁵ [∵aᵐ÷aₙ=aᵐ⁻ᵐ]
⇒ 5ᵐ⁺³ =5⁵
Comparing exponents both sides, we get
⇒ m+3=5
⇒ m=5-3
⇒ m=2
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Evaluate: 8⁻¹ x5³/2⁻⁴
8⁻¹ x5³/2⁻⁴ = (2³)⁻¹ x 5³/2⁻⁴ = 2⁻³x5³/2⁻⁴ [∵(aᵐ)ⁿ=aᵐˣⁿ] = 2⁻³(⁻⁴)x5³= 2⁻³⁺⁴x5³ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 2x125=250 Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
8⁻¹ x5³/2⁻⁴ = (2³)⁻¹ x 5³/2⁻⁴ = 2⁻³x5³/2⁻⁴ [∵(aᵐ)ⁿ=aᵐˣⁿ]
= 2⁻³(⁻⁴)x5³= 2⁻³⁺⁴x5³ [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ]
= 2×125=250
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Find the value of: (3⁰+4⁻¹)x2²
(3⁰+4⁻¹)x2² = (1+1/4)x2² [∵ a⁻ᵐ =1/aᵐ] = (4+1/4) x 2²=5/4x2²=5/2²x2² = 5x2²⁻² [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ] = 5x2⁰ = 5x1 = 5 [∵ a⁰=1] Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(3⁰+4⁻¹)x2² = (1+1/4)x2² [∵ a⁻ᵐ =1/aᵐ]
= (4+1/4) x 2²=5/4×2²=5/2²x2²
= 5×2²⁻² [∵ aᵐ÷aⁿ=aᵐ⁻ⁿ]
= 5×2⁰ = 5×1 = 5 [∵ a⁰=1]
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
Simplify and express the result in power notation with positive exponent:(-4)⁵ ÷(-4)⁸
(-4)⁵ ÷(-4)⁸ = (-4)⁵⁻⁸ = (-4)⁻³ = 1/(-4)⁸ Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/
(-4)⁵ ÷(-4)⁸ = (-4)⁵⁻⁸
= (-4)⁻³ = 1/(-4)⁸
Class 8 Maths Chapter 11 Exercise 12.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-12/