(i) (a ²) x (2a ²²) x (4a²⁶) = (2X4)(a²xa²²xa²⁶) = 8a²⁺²²⁺²⁶ = 8a⁵⁵ Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) (a ²) x (2a ²²) x (4a²⁶) = (2X4)(a²xa²²xa²⁶) = 8a²⁺²²⁺²⁶ = 8a⁵⁵
Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video
(i) 4px(q+r)=4pxq+4pxr = 4pq+4pr (ii) abx(a-b)=abxa-abxb = a²b-ab² Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) 4px(q+r)=4pxq+4pxr = 4pq+4pr
(ii) abx(a-b)=abxa-abxb = a²b-ab²
Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video
(i) xy X yz X zx = x X x X y X y x z x z = x²y²z² (ii) a x (-a²) X a³ = (-1)(axa²xa³) = -a⁶ Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) xy X yz X zx = x X x X y X y x z x z = x²y²z²
(ii) a x (-a²) X a³ = (-1)(axa²xa³) = -a⁶
Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video
(i) Volume of rectangular box = length x breadth x height = 5ax3a²x7a⁴=(5x3x7)(axa²xa⁴) = 105a⁷ cubic units (ii) Volume of rectangular box = length x breadth x height = 2px4qx8r= (2x4x8)(pxqxr) = 64 pqr cubic units Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: httpRead more
(i) Volume of rectangular box = length x breadth x height
= 5ax3a²x7a⁴=(5x3x7)(axa²xa⁴)
= 105a⁷ cubic units
(ii) Volume of rectangular box = length x breadth x height
= 2px4qx8r= (2x4x8)(pxqxr)
= 64 pqr cubic units
Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video
(i) 4x7 p = 4x7x p = 28 p (ii)-4px7p = (-4x7)x(pxp) = -28p² (iii)-4px7pq = (-4x7)x(pxpq)= -28p²q (iv) 4p³x-3p = (4x-3)(p³-p) = -12p⁴ (v) 4 px0 = (4x0)(p) = 0 Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/cRead more
Find the product: (a ²) x (2a ²²) x (4a²⁶)
(i) (a ²) x (2a ²²) x (4a²⁶) = (2X4)(a²xa²²xa²⁶) = 8a²⁺²²⁺²⁶ = 8a⁵⁵ Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) (a ²) x (2a ²²) x (4a²⁶) = (2X4)(a²xa²²xa²⁶) = 8a²⁺²²⁺²⁶ = 8a⁵⁵
Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Carry out the multiplication of the expressions in each of the following pairs: (i) 4p,q+r (ii) ab,a-b
(i) 4px(q+r)=4pxq+4pxr = 4pq+4pr (ii) abx(a-b)=abxa-abxb = a²b-ab² Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) 4px(q+r)=4pxq+4pxr = 4pq+4pr
(ii) abx(a-b)=abxa-abxb = a²b-ab²
Class 8 Maths Chapter 9 Exercise 9.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Obtain the product of: (i) xy, yz, zx (ii) a, -a²,a³
(i) xy X yz X zx = x X x X y X y x z x z = x²y²z² (ii) a x (-a²) X a³ = (-1)(axa²xa³) = -a⁶ Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
(i) xy X yz X zx = x X x X y X y x z x z = x²y²z²
(ii) a x (-a²) X a³ = (-1)(axa²xa³) = -a⁶
Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Obtain the volume of rectangular boxes with the following length, breadth and height respectively: (i) 5a, 3a²7a⁴ (ii) 2p,4q,8r
(i) Volume of rectangular box = length x breadth x height = 5ax3a²x7a⁴=(5x3x7)(axa²xa⁴) = 105a⁷ cubic units (ii) Volume of rectangular box = length x breadth x height = 2px4qx8r= (2x4x8)(pxqxr) = 64 pqr cubic units Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: httpRead more
(i) Volume of rectangular box = length x breadth x height
= 5ax3a²x7a⁴=(5x3x7)(axa²xa⁴)
= 105a⁷ cubic units
(ii) Volume of rectangular box = length x breadth x height
= 2px4qx8r= (2x4x8)(pxqxr)
= 64 pqr cubic units
Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Find the product of the following pairs of monomials: (i) 4,7p (ii) -4p,7p (iii) -4p,7pq (iv)4p³,-3p (iv) 4 ,0 p
(i) 4x7 p = 4x7x p = 28 p (ii)-4px7p = (-4x7)x(pxp) = -28p² (iii)-4px7pq = (-4x7)x(pxpq)= -28p²q (iv) 4p³x-3p = (4x-3)(p³-p) = -12p⁴ (v) 4 px0 = (4x0)(p) = 0 Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/cRead more
(i) 4×7 p = 4x7x p = 28 p
(ii)-4px7p = (-4×7)x(pxp) = -28p²
(iii)-4px7pq = (-4×7)x(pxpq)= -28p²q
(iv) 4p³x-3p = (4x-3)(p³-p) = -12p⁴
(v) 4 px0 = (4×0)(p) = 0
Class 8 Maths Chapter 9 Exercise 9.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/