The image coincides with the object, indicating that the object is at the focal point of the convex lens. Thus, the focal length of the lens is 20 cm, as the object distance equals the focal length. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
The image coincides with the object, indicating that the object is at the focal point of the convex lens. Thus, the focal length of the lens is 20 cm, as the object distance equals the focal length.
For a converging lens (f1 >0) and a diverging lens (f2 <0) with equal focal lengths (∣f1 ∣= ∣f2∣): 1/f = 1/f1 + 1/f2 = 1/f - 1/f = 0 Thus, the combination has infinite focal length and behaves like a plane glass. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physiRead more
For a converging lens (f1 >0) and a diverging lens (f2 <0) with equal focal lengths (∣f1 ∣= ∣f2∣):
1/f = 1/f1 + 1/f2 = 1/f – 1/f = 0
Thus, the combination has infinite focal length and behaves like a plane glass.
The power of a lens combination is the sum of the individual powers: P total = P1+ P2 Here, P1 = −4D and P2 = 2D : P total = −4+2=−2D The focal length f is related to the power by f = 100/P (in cm): f =100/−2 =−50 cm (or -0.5 m) Thus, the focal length of the combination is -50 cm. For more visit heRead more
The power of a lens combination is the sum of the individual powers:
P total = P1+ P2
Here, P1 = −4D and P2 = 2D :
P total = −4+2=−2D
The focal length f is related to the power by
f = 100/P (in cm):
f =100/−2 =−50 cm (or -0.5 m)
Thus, the focal length of the combination is -50 cm.
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D Hence, f = 1/p = - 1/2 m = -50 cm. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D
Hence, f = 1/p = – 1/2 m = -50 cm.
When a concave lens (n = 1.5) is immersed in a medium with a higher refractive index (n = 1.65), it behaves as a convex lens, as the medium bends light more strongly than the lens. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
When a concave lens (n = 1.5) is immersed in a medium with a higher refractive index (n = 1.65), it behaves as a convex lens, as the medium bends light more strongly than the lens.
A convex lens is placed in contact with a plane mirror. A point object at a distance of 20 cm on the axis of this combination has its image coinciding with itself. What is the focal length of the lens?
The image coincides with the object, indicating that the object is at the focal point of the convex lens. Thus, the focal length of the lens is 20 cm, as the object distance equals the focal length. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
The image coincides with the object, indicating that the object is at the focal point of the convex lens. Thus, the focal length of the lens is 20 cm, as the object distance equals the focal length.
For more visit here:
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A converging lens is kept coaxially in contact with diverging lens – both the lenses being of equal focal lengths. What is the focal length of the combination?
For a converging lens (f1 >0) and a diverging lens (f2 <0) with equal focal lengths (∣f1 ∣= ∣f2∣): 1/f = 1/f1 + 1/f2 = 1/f - 1/f = 0 Thus, the combination has infinite focal length and behaves like a plane glass. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physiRead more
For a converging lens (f1 >0) and a diverging lens (f2 <0) with equal focal lengths (∣f1 ∣= ∣f2∣):
1/f = 1/f1 + 1/f2 = 1/f – 1/f = 0
Thus, the combination has infinite focal length and behaves like a plane glass.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
Two thin lenses of power – 4D and 2D are placed in contact coaxially. What is the focal length of the combination?
The power of a lens combination is the sum of the individual powers: P total = P1+ P2 Here, P1 = −4D and P2 = 2D : P total = −4+2=−2D The focal length f is related to the power by f = 100/P (in cm): f =100/−2 =−50 cm (or -0.5 m) Thus, the focal length of the combination is -50 cm. For more visit heRead more
The power of a lens combination is the sum of the individual powers:
P total = P1+ P2
Here, P1 = −4D and P2 = 2D :
P total = −4+2=−2D
The focal length f is related to the power by
f = 100/P (in cm):
f =100/−2 =−50 cm (or -0.5 m)
Thus, the focal length of the combination is -50 cm.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
Two thin lenses of power + 6 D and – 2 D are in contact. What is the focal length of the combination?
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D Hence, f = 1/p = - 1/2 m = -50 cm. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D
Hence, f = 1/p = – 1/2 m = -50 cm.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
Q.23. A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. What is the nature of the lens?
When a concave lens (n = 1.5) is immersed in a medium with a higher refractive index (n = 1.65), it behaves as a convex lens, as the medium bends light more strongly than the lens. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
When a concave lens (n = 1.5) is immersed in a medium with a higher refractive index (n = 1.65), it behaves as a convex lens, as the medium bends light more strongly than the lens.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/