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Solve the following equations by trial and error method: 5p+2 =17

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NCERT Solutions for Class 7 Mathematics Chapter 4
Important NCERT Questions
Class vii Math Chapter 4 Simple Equations Exercise 4.1
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 3

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1 Answer

  1. 5p+2 =17
    Putting p = -3 in L.H.S. 5(-3)+2 = -15+2 =-13
    ∵ -13 ≠ 17 Therefore, p = -3 is not the solution.

    Putting p = -2 in L.H.S. 5(-2)+2 = -10+2 =-8
    ∵ -8 ≠ 17 Therefore, p = -2 is not the solution.

    Putting p = -1 in L.H.S. 5(-1)+2 = -5+2 =-3
    ∵ -3 ≠ 17 Therefore, p = -1 is not the solution.

    Putting p = 0 in L.H.S. 5(0)+2 = 0+2 = 2
    ∵ 2 ≠ 17 Therefore, p = 0 is not the solution.

    Putting p = 1 in L.H.S. 5(1)+2 = 5+2 = 7
    ∵ 7 ≠ 17 Therefore, p = 1 is not the solution.

    Putting p = 2 in L.H.S. 5(2)+2 = 10+2 = 12
    ∵ 12 ≠ 17 Therefore, p = 2 is not the solution.

    Putting p = 3 in L.H.S. 5(3)+2 = 15+2 = 17
    ∵ 17 ≠ 17 Therefore, p = 3 is the solution.

    Class 7 Maths Chapter 4 Exercise 4.1

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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