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Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

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NCERT Solutions for Class 7 Mathematics Chapter 2
Important NCERT Questions
Class vii Math Chapter 2 Fractions and Decimals Exercise 2.5
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 7

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1 Answer

  1. Distance travelled by Dinesh when he went from place A to place B = 7.5 km and from
    place B to C = 12.7 km.
    Total distance covered by Dinesh = AB + BC
    = 7.5 + 12.7 = 20.2 km
    Total distance covered by Ayub = AD + DC
    = 9.3 + 11.8 = 21.1 km
    On comparing the total distance of Ayub and Dinesh,
    21.1 km > 20.2 km
    Therefore, Ayub covered more distance by 21.1 – 20.2 = 0.9 km = 900 m

    Class 7 Maths Chapter 2 Exercise 2.5 Question 5, 6, 7

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

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