Iditri singh
  • 11

Using a²-b²=(a+b)(a-b), find (i) 51²-49² (ii) (1.02) ² – (0.98) ²

  • 11

NCERT Solutions for Class 8 Mathematics Chapter 9
Important NCERT Questions
Algebraic Expressions and Identities Chapter 9 Exercise 9.5
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 7

Share

1 Answer

  1. (i) 51²-49² =(51+49)(51-49) [Using identity (a-b)(a+b)=a²=b²]
    = 100 x 2 = 200
    (ii) (1.02)² – (0.98)²= (1.02-0.98)(1.02-0.98) [Using identity (a-b)(a+b)=a²=b²]
    = 2.00 x 0.04 = 0.08

    Class 8 Maths Chapter 9 Exercise 9.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/

    • 7
Leave an answer

Leave an answer

Browse