Use a suitable identity to get each of the following products: (i) (x+3)(x+3) (ii) (2y+5) (2y+5)

(i) (x+3)(x+3) = (x+3)²
= (x)²+2 X x X 3 +(3)² [Using identity (a+b)² =a²+2ab+b²]
= x²+6x+9
(ii) (2y+5) (2y+5)
= (2y)²+2X2yx5+(5)²
= 4y²+20y+25

Class 8 Maths Chapter 9 Exercise 9.5 Solution in Video

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