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Using divisibility test, determine which of the following numbers are divisible by 11: (a) 5445 (b) 10824 (c) 7138965 (d) 70169308 (e) 10000001 (f) 901153

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NCERT Solutions for Class 6 Maths Chapter 3
Important NCERT Questions
Playing With Numbers Chapter 3 Exercise 3.3
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 4

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  1. (a) 5445 → Sum of the digits at odd places = 4 + 5 = 9
    → Sum of the digits at even places = 4 + 5 = 9
    → Difference of both sums = 9 – 9 = 0
    Since the difference is 0, therefore, the number is divisible by 11.
    (b) 10824 → Sum of the digits at odd places = 4 + 8 +1 = 13
    → Sum of the digits at even places = 2 + 0 = 2
    → Difference of both sums = 13 – 2 = 11
    Since the difference is 11, therefore, the number is divisible by 11.
    (c) 7138965 → Sum of the digits at odd places = 5 + 9 + 3 + 7 = 24
    → Sum of the digits at even places = 6 + 8 + 1 = 15
    → Difference of both sums = 24 – 15 = 9
    Since the difference is neither 0 nor 11, therefore, the number is not divisible by 11.
    (d) 70169308 → Sum of the digits at odd places = 8 + 3 + 6 + 0 = 17
    → Sum of the digits at even places = 0 + 9 + 1 + 7 = 17
    → Difference of both sums = 17 – 17 = 0
    Since the difference is 0, therefore, the number is divisible by 11.
    (e) 10000001 → Sum of the digits at odd places = 1 + 0 + 0 + 0 = 1
    → Sum of the digits at even places = 0 + 0 + 0 + 1 = 1
    → Difference of both sums = 1 – 1 = 0
    Since the difference is 0, therefore, the number is divisible by 11.
    (f) 901153 → Sum of the digits at odd places = 3 + 1 + 0 = 4
    → Sum of the digits at even places = 5 + 1 + 9 = 15
    → Difference of both sums = 15 – 4 = 11
    Since the difference is 11, therefore, the number is divisible by 11.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/

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