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Kriti
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Asked: 2026-10-14T05:54:38+00:00 In:

The variation of density of medium for a sound wave propagating with a speed of 340 m s⁻¹ is shown in Fig. 10.32. Calculate the wavelength and frequency of the sound wave.

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The 8 cm span covers two consecutive wavelengths, giving a wavelength of 4 cm or 0.04 m. Dividing the speed of 340 m s⁻¹ by 0.04 m yields 8500 Hz.

Chapter 10 Sound Waves Characteristics and Applications Solutions
Sound Waves Characteristics and Applications Exercise Solutions

8 cm span covers two consecutive wavelengthsclass 9 science exploration chapter 10 sqp from tiwari academydividing the speed of 340 m s⁻¹ by 0.04 m yields 8500 hzhalf yearly exam questions – sound waves: characteristics and applicationssample question from class 10 science sound waves chapter 10
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    1 Answer

    1. (i) Wavelength: The marked distance of 8 cm spans across two full compression-to-compression cycles, meaning two wavelengths equal 8 cm. Thus, the wavelength is 4 cm, which equals 0.04 m. (ii) Frequency: Using the wave relation where frequency equals speed divided by wavelength, dividing 340 m s⁻¹ by 0.04 m gives a frequency of 8500 Hz (or 8.5 kHz).

       

      For more NCERT Solutions of Class 9 Science Exploration Chapter 10 Sound Waves Characteristics and Applications Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-10/

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