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Asked: 2026-10-07T07:10:51+00:00 In:

In a cyclic quadrilateral ABCD, ∠A = (x + 7)°, ∠B = (y + 8)°, ∠C = (3y + 23)° and ∠D = (4x + 12)°. Find all four angles of the cyclic quadrilateral.

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Opposite angles sum to 180°, giving x + 3y = 150 and 4x + y = 160. Solving gives x = 30 and y = 40. The angles are ∠A = 37°, ∠B = 48°, ∠C = 143° and ∠D = 132°.

Ganita Manjari Class 9 Maths part 2 Chapter 13 Solutions

Class 9 Ganita Manjari Part 2 Chapter 13 Page 121 Question Answer

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    1. In a cyclic quadrilateral, opposite angles are supplementary. Thus, ∠A + ∠C = (x + 7) + (3y + 23) = 180°, which simplifies to x + 3y = 150. Also, ∠B + ∠D = (y + 8) + (4x + 12) = 180°, giving 4x + y = 160. Multiplying the first equation by 4 and subtracting the second eliminates x, yielding 11y = 440, so y = 40 and x = 30. The angles are 37°, 48°, 143° and 132°.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

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