Slant height is √(8² + 6²) = 10 m. Curved surface area is 3.14 × 6 × 10 = 188.4 m². Dividing by width 3 m gives 62.8 m. Adding 0.2 m wastage gives total length 63 m.
Class 9 Ganita Manjari Part 2 book Solutions
Chapter 14 Math of Space Surface Area and Volume (Ganita Manjari 2) Solutions
Given height h = 8 m and radius r = 6 m, slant height is l = √(8² + 6²) = 10 m. Curved surface area of the tent is πrl = 3.14 × 6 × 10 = 188.4 m². Required tarpaulin length before wastage is 188.4 / 3 = 62.8 m. Adding extra length of 20 cm = 0.2 m for stitching and wastage yields a total required length of 62.8 + 0.2 = 63 m.
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