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Asked: 2026-10-03T04:21:47+00:00 In:

Suvarna had purchased 1g gold at ₹15k (short for ₹15,000). This is shown by point O denoting the average price of gold that she possesses. Six different scenarios are given below for her next transaction. For each scenario estimate and mark the average price of gold she will have after the transaction. (i) Purchase 1g gold at ₹30k (ii) Purchase 2g gold at ₹30k (iii) Purchase 1g gold at ₹10k (iv) Purchase 10g gold at ₹10k (v) Purchase 0.5g gold at ₹30k (vi) Purchase 0.5g gold at ₹15k.

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The updated averages are: (i) 22.5k (midpoint), (ii) 25k, (iii) 12.5k (midpoint), (iv) 10.45k (close to 10), (v) 20k and (vi) 15k (remains unchanged at point O).

Class 9 Maths How Quantities Combine Understanding Data Question Answer
Class 9 Maths Ganita Manjari Part 2 Chapter 10 Question And Answer

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    1. Calculating each weighted average: (i) [(1 × 15) + (1 × 30)]/2 = 22.5k (mark midway between 15 and 30). (ii) [15 + (2 × 30)]/3 = 25k. (iii) [(1 × 15) + (1 × 10)]/2 = 12.5k. (iv) [15 + (10 × 10)]/11 ≈ 10.45k (near 10k). (v) [15 + (0.5 × 30)]/1.5 = 20k. (vi) [15 + (0.5 × 15)]/1.5 = 15k (remains exactly at O).

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/

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