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Find two solutions which lie in different quadrants for the linear equation 5x + 3y = 7 and identify the quadrants.

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For x = 2, y = -1, giving the point (2, -1) in Quadrant IV. For x = -1, y = 4, giving the point (-1, 4) in Quadrant II. Both satisfy the equation.

Class 9 Maths Ganita Manjari Part 2 chapter 13 question answer
Class 9 Maths Ganita Manjari Part II Two Variables, One Line Solutions

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1 Answer

  1. Choosing x = 2 yields 5(2) + 3y = 7, which simplifies to 3y = -3, giving y = -1. This solution represents the point (2, -1) located in Quadrant IV. Choosing x = -1 gives 5(-1) + 3y = 7, simplifying to 3y = 12, giving y = 4. This solution is the point (-1, 4), which lies in Quadrant II.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

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