Both triangles PCD and QCD share the common base CD and lie between parallel lines AB and CD, giving identical perpendicular heights. Hence their areas are equal, and the ratio area(ΔPCD) : area(ΔQCD) is 1:1.
ABCD is a parallelogram. P and Q are any two points on side AB. What can you say about the ratio area (ΔPCD): area (ΔQCD)?
Share
Triangles PCD and QCD stand on the exact same base CD.
Because ABCD is a parallelogram, the line AB containing points P and Q is parallel to side CD.
Triangles on the same base and between the same parallel lines have identical altitudes (perpendicular heights) to that base.
Area(ΔPCD) = (1/2) x CD x height
Area(ΔQCD) = (1/2) x CD x height
Since bases and heights are identical, Area(ΔPCD) = Area(ΔQCD).
Thus, the ratio area(ΔPCD) : area(ΔQCD) is 1:1.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/