(i) One revolution covers circumference π x d = (22/7) x 56 = 176 cm (1.76 m).
(ii) In 10 km (1,000,000 cm), number of revolutions is 1000000 / 176 = 5681.82, or approximately 5682 revolutions.
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Diameter of tyre d = 56 cm, so radius r = 28 cm.
(i) Distance covered in one revolution equals the tyre’s circumference:
Distance = π x d = (22/7) x 56 = 22 x 8 = 176 cm = 1.76 m.
(ii) Total distance = 10 km = 10 x 1000 x 100 cm = 1,000,000 cm.
Number of revolutions = Total distance / Circumference
= 1000000 / 176 = 62500 / 11 = 5681.82.
Hence, the tyre completes approximately 5682 revolutions.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/