Total tyres recorded equal 1000. The required probabilities are: (i) 20 / 1000 = 0.02, (ii) (210 + 325) / 1000 = 535 / 1000 = 0.535 and (iii) 445 / 1000 = 0.445.
A tyre company records distances before replacement in 1000 cases. Find the probability that a randomly chosen tyre lasts: (i) Less than 4000 km, (ii) Between 4000 and 14000 km, (iii) More than 14000 km.
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Total number of cases = 1000.
(i) For tyre lasting less than 4000 km, frequency = 20. Probability = 20 / 1000 = 0.02 (or 2%).
(ii) For distance between 4000 and 14000 km, add frequencies (4001 to 9000 km) and (9001 to 14000 km): 210 + 325 = 535. Probability = 535 / 1000 = 0.535 (or 53.5%).
(iii) For tyre lasting more than 14000 km, frequency = 445. Probability = 445 / 1000 = 0.445 (or 44.5%).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/