For the first 120 s, displacement = 6 × 120 = 720 m. During the next 6 s, displacement = 6 × 6 + ½ × 1 × 6² = 54 m. Total displacement = 774 m.
On entering a state highway, a car continues to move with a constant velocity of 6 m s⁻¹ for 2 minutes and then accelerates with a constant acceleration 1 m s⁻² for 6 seconds. Find the displacement of the car on the state highway in the 2 min 6 s time interval by drawing a velocity-time graph for its motion.
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For the first 2 minutes = 120 s, the car moves at 6 m s⁻¹. Therefore, displacement = 6 × 120 = 720 m. During the next 6 s, initial velocity is 6 m s⁻¹ and acceleration is 1 m s⁻². Displacement = ut + ½at² = 6 × 6 + ½ × 1 × 36 = 54 m. Hence, total displacement = 720 + 54 = 774 m.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/