Expanding the left side yields 3a square + 3b square + 3c square – 2ab – 2bc – 2ca, which does not match the right side. Therefore, the given mathematical equation is false.
Is this an identity? (a + b – c) square + (a – b + c) square + (a – b – c) square = 2a square + 2b square + 2c square
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