The least common multiple (LCM) of 4, 9 and 10 is 180. The smallest square divisible by 180 is 900, since 30² = 900. So, the required smallest square number divisible by 4, 9 and 10 is 900.
Class 8 Mathematics Textbook Chapter 1 A Square and A Cube question answer
Class 8 Mathematics Chapter 1 A Square and A Cube solutions
To find the smallest square divisible by 4, 9 and 10, we first compute their LCM:
4 = 2², 9 = 3², 10 = 2 × 5 ⇒ LCM = 2² × 3² × 5 = 180.
Now find the smallest perfect square that includes all these prime factors in even powers. 900 = 2² × 3² × 5² = 30², which is a perfect square and divisible by 180.
Answer: 900.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
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