Hriday Saini
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Poll

When a current of 5 mA is passed through galvanometer having a coil of resistance 15 Ω, it shows full scale deflection. The value of the a be resistance to be put in series with the galvanometer to convert it into to voltmeter of range 0-10 V is

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Poll Results

0%(A) 2.535 × 10³ Ω
0%(B) 4.005 × 10³ Ω
100%(C) 1.985 × 10³ Ω ( 1 voter )
0%(D) 2.045 × 10³ Ω
Based On 1 Vote

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To convert the galvanometer to a voltmeter of range 0–10 V, the series resistance
R is given by: R = V/I – Rg
Substituting V = 10V, I = 5 mA and Rg = 15 Ω:
R = 10/0.005 – 15 = 2000 – 15 = 1985 Ω
Answer: (C) 1.985 × 10³ Ω.

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1 Answer

  1. To convert a galvanometer to a voltmeter, the series resistance (R) is calculated as:

    V = I(Rg + R)
    Where:
    V = 10 volts
    I = 5 mA = 0.005 A
    Rg = 15Ω

    10 = 0.005 × (15+R)
    15 + R = 10/0.005 = 2000
    R = 2000 −15 = 1985Ω
    Answer: (C) 1.985 × 10³ Ω

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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