If from a point A which is at distance of 13 cm from the centre O of a circle of radius 5cm, the pair of tangent AB and AC to the circle are drawn, then the area of quadrilateral ABOC is
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Given:
– OA = 13 cm, OB = OC = 5 cm (radius),
– Tangent length AB = AC = √(OA² – OB²) = √(13² – 5²) = 12 cm.
Area of ΔABO = (1/2) × AB × OB = (1/2) × 12 × 5 = 30 cm².
Similarly, Area of ΔACO = 30 cm².
Total area of ABOC = 30 + 30 = 60 cm².
This question pertains to Chapter 10 of the Class 10th NCERT Mathematics textbook, specifically the chapter on “Circles.” Provide your answer in accordance with the knowledge and understanding you have gained from studying this chapter.
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