Oxygen’s ability to stabilize high oxidation states surpasses that of fluorine, as seen in the highest fluoride (MnF₄) and oxide (Mn₂O₇) of manganese, highlighting oxygen’s superiority in forming multiple bonds to metals.
How does the ability of oxygen to stabilize high oxidation states compare to that of fluorine, and what is an example illustrating this superiority in the context of manganese?
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Oxygen’s ability to stabilize high oxidation states surpasses that of fluorine. An illustrative example is the comparison between manganese fluoride (MnF₄) and the highest oxide, manganese heptoxide (Mn₂O₇). While MnF₄ represents the highest fluoride, Mn₂O₇ demonstrates the superior stabilizing effect of oxygen. The ability of fluorine to stabilize high oxidation states is limited, leading to MnF₄ as the highest fluoride. In contrast, oxygen, with its stronger bonding ability, facilitates the formation of Mn₂O₇, showcasing its superiority in stabilizing higher oxidation states in transition metal compounds compared to fluorine.