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girish08
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Asked: 2023-02-14T10:16:51+00:00 In:

In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:

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(i) sin A, cos A

(ii) sin C, cos C

How to solve NCERT Class 10 Chapter 8 Introduction to Trigonometry Question?

Exercise 8.1

Question No. 1

Page No.  181

 

chapter 8class 10ncert
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    1. Best Answer
      In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:

      In △AABC, by Pythagoras theorem, we have
      AC² = AB²+BC²
      = (24 cm)²+(7 cm)²
      = (576 + 49)cm²
      = 625 cm²
      ⇒ AC = √625 = 25 cm
      (i) sin A = BC/AC = 7/25 and cos A = AB/AC = 24/25
      (ii) sin C = AB/AC = 24/25 and cos C = BC/AC = 7/25

      See here for video explanation of this above question 😁✌

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